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Fri, 18 Feb 2022 11:08:35 . . . . (Paul Simoens)? [Misrepresented formula]

Changes by last author:

Added:
= hypot =

== Syntax ==

double hypot(double fx, double fy)

== Arguments ==

:fx

::First distance.

:fy

::Second distance.

== Return ==

The euclidean distance of the two parameters.

== Description ==

Calculates the hypothenuse (euclidean distance):

The distance between the endpoint of two adjacent perpendicular distances.

Solves Pythagoras formula; distance =sqrt( pow( fx, 2.0) +pow( fy, 2.0));

ATTENTION! works extremely slow! Use it only for an occasional calculation!